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A coin is tossed 6 times. Calculate probability of getting:
(a) exactly four heads
(b) at least four heads
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| (b) |  |
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Algorithm: Determine N (# of experiment)
Set E4H = 0 (Exacly 4 Head)
Set AL4H = 0 (At Least 4 Heads)
LOOP1 from i=0 to N
Set Head = 0
LOO2 k=1,6
Generate a random number R
from a uniform distribution
Check IF R<0.5 THEN
Increment Head by 1
END IF
END LOO2
Check IF Head =4 Increment E4H by 1
Check IF Head>=4 Increment AL4H by 1
END LOOP1
OUTPUT N, E4H/N, AL4H/N
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Output: N (a) (b)
------------- --------- ---------
10 0.1000000 0.3000000
100 0.3400000 0.4600000
1,000 0.2360000 0.3380000
10,000 0.2342000 0.3393000
100,000 0.2328500 0.3430800
1,000,000 0.2346350 0.3438360
10,000,000 0.2343817 0.3434362
100,000,000 0.2343522 0.3437505
1,000,000,000 0.2343743 0.3437576
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